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18x^2+3x-12x-2=0
We add all the numbers together, and all the variables
18x^2-9x-2=0
a = 18; b = -9; c = -2;
Δ = b2-4ac
Δ = -92-4·18·(-2)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-15}{2*18}=\frac{-6}{36} =-1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+15}{2*18}=\frac{24}{36} =2/3 $
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